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+30.4+12x=4.9x^2
We move all terms to the left:
+30.4+12x-(4.9x^2)=0
We get rid of parentheses
-4.9x^2+12x+30.4=0
a = -4.9; b = 12; c = +30.4;
Δ = b2-4ac
Δ = 122-4·(-4.9)·30.4
Δ = 739.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-\sqrt{739.84}}{2*-4.9}=\frac{-12-\sqrt{739.84}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+\sqrt{739.84}}{2*-4.9}=\frac{-12+\sqrt{739.84}}{-9.8} $
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